Help with Matlab homework question

𝑋𝑛+1 = 𝑋𝑛 2 + 0.25

Considering the relation, calculate and record the value of the relation for each value of n,

Write a computer program that will output the result for only n = 0, 5, 10, 15,… values.

n = 0,1,2,3,…., N

N=54

[David Hill]

What have you done? You need a starting value of X at some point, for example X(12)=5 or X(0)=1.

[polat kayhan]

x(0)=0

[polat kayhan]

you can give the first value yourself x(0)= 1 or x(0)= 0

[Image Analyst]

There is something missing between the n and the 2.

Do you mean x(n+1) = x(n) * 2 + 0.25 or what????

n = 0 : N
x(1) = 0;
for k = 2 : length(n)
    index = n(k) + 1; % Index can't start at 0.  It needs to start at 1.
    x(index + 1) = x(index) * 2 + 0.25;
end
x % Show x for all values of n in command window.

Answer 1

[Sulaymon Eshkabilov]

Use colon operator ":" to generate the series of x(n+1). And to select or take out only n = 0, 5, 10, 15,…54 values, use again ":", e.g. 1:5:54

Good luck.

[polat kayhan]

n=0; x_(n+1)=2; x_n=1;

for n= 0:1:54;

x_(n+1)= (x_n)^2+(1/4);

n=n+1;

end

for n=0:5:54;

x_(n+1)= (x_n)^2+(1/4);

disp(x_(n+1))

n=n+5;

end

is it correct ?

Answer 2

[Sulaymon Eshkabilov]

What you are computing is not quite correct. But you have done some attempt.

Here is a simple solution

n = 1:54;
x(1)=0;
for ii = n
 x(ii+1)=x(ii)^2+.25;
end
X_out = x(1:5:54);
OUT = [(0:5:54);X_out];
fprintf('  n         Output:   \n')
fprintf('x(%d) = %f \n', OUT)

[polat kayhan]

thank you very much <3

[Sulaymon Eshkabilov]

So what?