How can I use data from .mat file into spline function?
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I used the ginput function to select a lot of points, who were stored into a 'data.mat' file.
I now need to use the x and y coordinates into the spline function, which are saved into 'data.mat', but I don't know how to "call" the coordinates from the 'data.mat' file.
I already loaded the data:
S = load('dados.mat');
And I already have the plot ready, I just don't know how to "call" the x and y values.
x =
y =
xx = linspace(0,500,100);
yy = spline(x,y,xx);
figure;
plot(x, y, 'ro');
hold on;
plot(xx, yy, 'b', 'LineWidth', 1.5);
댓글 수: 5
Stephen23
2021년 6월 18일
편집: Stephen23
2021년 6월 18일
@Hélio Filho:
It is much more robust to load into an output variable (which is a scalar structure), just as you wrote in your question:
S = load(...)
and then access the fields of that structure, e.g.:
S.x
S.y
Either way you need to know and use the exact names of the data stored in the .mat file, which you can either get from the structure S (e.g. looking at it in the Variable Viewer or using fieldnames), or without even loading the filedata:
whos -file filename
Your original approach of loading into a structure is much better (it is less liable to bugs and easier to debug):
채택된 답변
Sulaymon Eshkabilov
2021년 6월 17일
Here is the corrected code:
...
save('data.mat', 'x','y'); % Your variable names called x, y and you need to save them here
load data.mat
end
xx = linspace(0,500,100);
yy = spline(x,y,xx);
figure;
plot(x, y, 'ro'); % x, y from ginput (data.mat)
hold on;
plot(xx, yy, 'b', 'LineWidth', 1.5);
댓글 수: 2
Stephen23
2021년 6월 18일
It is much more robust to load into an output variable (which is a scalar structure), just as the question shows:
S = load(...)
and then access the fields of that structure, e.g.:
S.x
S.y
추가 답변 (1개)
Sulaymon Eshkabilov
2021년 6월 17일
If all the data of x, y are saved under X, Y names from ginput in a sequenctial order in DATA.mat file.
You can load them and eploy, e.g.:
load DATA.mat
% x, y values will be in the MATLAB workspace
% Your code comes here
xx = linspace(0,500,100);
yy = spline(X,Y,xx);
...
댓글 수: 2
Stephen23
2021년 6월 18일
It is much more robust to load into an output variable (which is a scalar structure), just as the question shows:
S = load(...)
and then access the fields of that structure, e.g.:
S.x
S.y
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