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Is there a better way to solve this multidimensional array?

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Bianka Markovic
Bianka Markovic 2021년 6월 11일
댓글: Bianka Markovic 2021년 6월 14일
Hello to everyone,
I'm currently trying to calculate annual temperatures and temperature anomalies. The data is given in one variable (here the M variable). It entails the temperatures for different longitude and latitude (basically temperatures on a regular grid), different depth and time. The first entry is the longitude and the second the latitude. The third one is for the different depth and the forth the time. The time represents 24 years, 12 entries per year meaning one temperature value for each month of the year.
The first loop is working fine even thou it takes some time. But the second loop takes too much time and effort that it never got through before my laptop broke down.
Does anyone knows maybe why it is not working, or has anyone a suggestion how could I make the program more efficient?
Thank you!
M=rand(1920,374,6,288);
sizetemp=size(M);
temp_mean=[];
for i=1:sizetemp(1); %longitude
for j=1:sizetemp(2); %latitude
for k=1:sizetemp(3) %depth
temp_mean(i,j,k)=mean(M(i,j,k,:));
end
end
end
m=1;
temp_annual=[];
an_temp=[];
for i=1:sizetemp(1); %longitude
for j=1:sizetemp(2); %latitude
for k=1:sizetemp(3) %depth
for l=1:12:sizetemp(4);
temp_annual(i,j,k,m)=mean(M(i,j,k,l:l+11));
an_temp(i,j,k,m)=temp_mean(i,j,k)-temp_annual(i,j,k,m);
m=m+1;
end
end
end
end

채택된 답변

SALAH ALRABEEI
SALAH ALRABEEI 2021년 6월 11일
For the first averaging
%
temp_mean = nanmean(M,4);
For the 2nd annual avg use
%
A=reshape(M,19,3,6,size(M,4)/12,12);
an_temp = nanmean(A,5);
  댓글 수: 1
Bianka Markovic
Bianka Markovic 2021년 6월 14일
Thank you for your answer Salah Alrabeei,
unfortunately the program shows an error:
Error using reshape
To RESHAPE the number of elements must not change.
Error in test (line 44)
A=reshape(M,19,3,6,size(M,4)/12,12 );

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추가 답변(1개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2021년 6월 11일
Use mean2() intead of mean() that will help you to get rid of all loops.

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