extract one of the bits in fi(), flip it, and reassemble it to produce new bin

Hi, I am trying to do the following cleanly in fixed point designer:

Take a binary: '0010'

Flip the 2nd bit to produce: '0000'

Is there a clean way to do this with some opeartion within fi(), perhaps just 1 or 2 lines of code?

I am a new user at fixed-point designer.

Thank you very much.

Answer 1

[Hrishikesh Borate]

Hi,

It’s my understanding that you are trying to flip the bit at 2nd position.

Following is the code for the same :-

input = '0010';
bitflip = @(val, n) bitxor(val, 2.^(n-1));
output = dec2bin(bitflip(bin2dec(input),2));

For more information, refer to the following answer and dec2bin.

Answer 2

[Walter Roberson]

input = '1010';
input(3) = 'a' - input(3)

input = '1000'

... It's magic ;-)

flipped = (1 - (x - '0')) + '0'
flipped = 1 + '0' + '0' - x
flipped = 1 + 48 + 48 - x
flipped = 97 - x
flipped = 'a' - x

Answer 3

[Andy Bartlett]

Please see my answer in your similar question.

That answer provides a one-liner that works in most cases.

It also provides a more general solution using a helper function.