Average values only next to each other in a matrix

조회 수: 1 (최근 30일)
Jimmy Neutron
Jimmy Neutron 2021년 4월 16일
답변: David Hill 2021년 4월 16일
I have a matrix as such: (it is much longer irl)
A = [ 62.9; 63; 83.10; 83; 43; 43; 63; 63.2; 82.9; 83; 83; 62.90; 62.90; 62.9 ];
I am looking for an efficient way to average the values that surround the values next to each that are almost identical ( +- 0.2) other as such:
A_final = [ 62.95; 83; 43; 63.1, 83; 62.90 ]
I was thinking to do it with unique, but then I risk the possibility of the same value coming up in matrix A. Is there a simple way to do so in matlab?
  댓글 수: 2
the cyclist
the cyclist 2021년 4월 16일
Step 1: Define "almost identical" mathematically.
Jimmy Neutron
Jimmy Neutron 2021년 4월 16일
Added it :) it is plus minus 0.2

댓글을 달려면 로그인하십시오.

채택된 답변

David Hill
David Hill 2021년 4월 16일
I don't think there is an easy way, but a simple loop works.
A = [ 62.9; 63; 83.10; 83; 43; 43; 63; 63.2; 83; 83; 62.90; 62.90 ];
A_final=[];
b=A(1);
c=1;
for k=2:length(A)
if A(k)<1.1*b/c&&A(k)>.9*b/c
b=b+A(k);
c=c+1;
else
A_final=[A_final;b/c];
b=A(k);
c=1;
end
end
A_final=[A_final;b/c];

추가 답변 (1개)

Ahmed Redissi
Ahmed Redissi 2021년 4월 16일
You can reshape the n by 1 vector so that it is 2 by n/2 and then take the mean which will calculate the average for each column and give you the result that you want. Here is how it is done:
A = [62.9; 63; 83.10; 83; 43; 43; 63; 63.2; 83; 83; 62.90; 62.90];
n = length(A);
A_shaped = reshape(A,2,n/2);
A_final = mean(A_shaped)';

카테고리

Help CenterFile Exchange에서 Function Creation에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by