Creating an algorithm for a Simultaneous Equation

3000x + 1000y = 35000 (1)

240x + 5y = 1665 (2)

Please can you help me create an algorithm that will keep increasing the value of 3000 by 20% (i.e 3000 + 20%*3000) and at the same time giving the corresponding results of "x" and "y".

Thank you in anticipation.

Answer 1

[David Hill]

k=3000*(.2).^(0:10);%however long you want
for j=1:length(k)
  A=[k(j) 1000;240 5];
  b=[35000;1665];
  out(j,:)=A\b;
end

[Abdullahi Abubakar]

Thanks very much