How would I write this code using for and while loops/

조회 수: 1 (최근 30일)
Olivia Gilliam
Olivia Gilliam 2021년 2월 11일
편집: Sourabh Kondapaka 2021년 2월 18일
  댓글 수: 4
David Hill
David Hill 2021년 2월 11일
You could use if statement
for i=1:length(V)
if V(i)
V(i)=0;
else
V(i)=1;
end
end
Olivia Gilliam
Olivia Gilliam 2021년 2월 11일
Yeah I finally figured out 2a of the problem. Im working on 2b, so I'm trying to flip every second instance of 0. If I do it right, array V (V = [1, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1]), should become V = [1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1]. I underlined the zeroes that should flip to ones.
This is the code I used:
But, instead of getting V = [1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1]
I get:
Any help?

댓글을 달려면 로그인하십시오.

답변 (1개)

Sourabh Kondapaka
Sourabh Kondapaka 2021년 2월 17일
편집: Sourabh Kondapaka 2021년 2월 18일
I would recommend you to check out the free Matlab OnRamp Course
For 2b:
V = [1, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1];
count = 0;
for i = 1 : length(V)
% Below 'if' condition is same as : if V(i) == 0
if ~V(i)
count = count + 1;
% As you want to modify every second instance, i'm just checking the modulus value of count
% with 2.
if mod(count,2) == 0
V(i) = 1;
end
end
end

카테고리

Help CenterFile Exchange에서 Cell Arrays에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by