Remove rows or cols whose elements are all NaN

How can I remove rows or cols whose elements are all NaN ? Withouot any dirty iterations?
For example,
A = [1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;
1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;];
should turned into
A = [1 1 1 1 1 1 1 1 1 1;
1 1 1 1 1 1 1 1 1 1];
This is just an example. Actually I have a very big matrix. So I want a solution of this question to work well with my big matrix.

댓글 수: 2

Dev-iL
Dev-iL 2014년 7월 13일
편집: Dev-iL 2014년 7월 13일
Hi! You can find some clues here: A discussion of the opposite problem on SE. I personally achieved what you were attempting using:
A(~any(~isnan(A), 2),:)=[];
Michal Gajewski commented
works

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 채택된 답변

Andrei Bobrov
Andrei Bobrov 2013년 3월 25일
편집: Andrei Bobrov 2013년 3월 25일

24 개 추천

out = A(all(~isnan(A),2),:); % for nan - rows
out = A(:,all(~isnan(A))); % for nan - columns

댓글 수: 6

A can be a row-vector, such that all will operate along the 2nd dimension automatically. Therefore this is safer:
out = A(:, all(~isnan(A), 1));
HUGO LOYA
HUGO LOYA 2014년 6월 18일
Why do you write 1 for columns and 2 for rows?
Jan
Jan 2014년 7월 13일
@Hugo: See doc all for details. The numbers specify the dimension to operate on.
Can I obtain a logical matrix I of indices to be held / removed something like
I = something here
and then use assign an altered matrices:
out1 = out1(I);
out2 = out2(I);
% ... etc.
Thanks
gringer45
gringer45 2018년 3월 18일
This doesn't really do what the question asks for. This selects all the columns or rows with none (zero) NaN values. So, this is answering the question: "Remove rows or cols whose elements have any (at least one) NaN"
Adding on what @gringer45 said. The code to remove columns and/or rows with all NaN's is below.
A(:,~all(isnan(A))) % for all nan - columns
A(~all(isnan(A),2),:) % for all nan - rows

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추가 답변 (6개)

Phillippe
Phillippe 2015년 1월 14일

13 개 추천

To remove only ALL-NaN columns, do this instead:
A = A(:,~all(isnan(A)));
Saman
Saman 2013년 10월 23일
편집: Saman 2013년 10월 23일

4 개 추천

Use this :
out = A(:,any(~isnan(A))); % for columns
out = A(any(~isnan(A),2),:); %for rows
Azzi Abdelmalek
Azzi Abdelmalek 2013년 3월 25일

2 개 추천

A(isnan(A))=[]

댓글 수: 6

Jan
Jan 2013년 3월 25일
This does not solve the wanted: "delete rows or cols whose elements are all NaN"
I am not sure what he want, from his example his rows are all 1 or all nan! In this case the answer solve his problem.
Your answer will create an array. he wants to keep the matrix.
To delete rows with all NaN's, maybe try this:
A = A(find(sum(~isnan(A)'))',:)
A(all(isnan(A),2),:) = []; %rows that are all nan
A(:, all(isnan(A),1)) = []; %cols that are all nan
Andrew Sol
Andrew Sol 2024년 11월 14일
You proposed too simple a solution and you were wrong.

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Alfaz Memon
Alfaz Memon 2018년 8월 20일
편집: Alfaz Memon 2018년 8월 21일

1 개 추천

input varibale : data
output variable : row_index( index of rows with all the value as NaN)
row_index( index of rows with all the value as NaN)
column_index( index of columns with all the value as NaN)
if(iscell(data))
x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
[ia,ib] = ind2sub(size(data),x);
rows_unique = unique(ia);
rows_unique(:,2)=histc(ia,rows_unique);
row_index = rows_unique(find(rows_unique(:,2)==size(data,2)),1);
columns_unique = unique(ib);
columns_unique(:,2)=histc(ib,columns_unique);
column_index = rows_unique(find(columns_unique(:,2)==size(data,1)),1);
else
row_index =find(~any(~isnan(data), 2)); % row with all NaN values
column_index =find(~any(~isnan(data), 1)); %column with all NaN values
end

댓글 수: 2

Seems like a bit of a bother to just remove the rows or columns ?
I notice that you are using cellfun on the data, implying that the data is a cell array; in the original question it was a plain array.
Alfaz Memon
Alfaz Memon 2018년 8월 21일
편집: Alfaz Memon 2018년 8월 21일
yeah its for cell array. for plain array you can remove cellfun and just simply keep any(isnan(data),2) instead of x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
this can you work for cell array of different data type.
Also I have updated solution.

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Ilham Hardy
Ilham Hardy 2013년 3월 25일

0 개 추천

Haven't tried this, but it should works:
A(isnan(A))=[];

댓글 수: 1

Jan
Jan 2013년 3월 25일
This does not solve the wanted: "delete rows or cols whose elements are all NaN"

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Nike
Nike 2013년 3월 25일

0 개 추천

Simplest is
A(isnan(A))= [];

댓글 수: 1

This has been posted twice already. But it still does not solve the original question:
delete rows or cols whose elements are all NaN
For e.g. A = [1, NaN, 1; NaN, 1, NaN] nothing should be deleted.

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