Creating a Tridiagonal Matrix with varying values

Hello, I am trying to create a tridiagonal matrix with varying values. As shown in the image below
the main diagonal is able to have varying value, but the code only works if the offsetting diagonals are constant values. I am attempting to have all 3 diagonals be varying numerals any help would be greatly appreciated. I will attach my code below.
function [A,b] = ok(k,m)
A=[k];
n=size(A,2)
b=[m];
if size(b,2) < 1
b=[m];
else
b=[m]';
j=size(b,2);
end
N = n;
a = -k;
d =4;
c =4;
M = zeros(N,N)
M( 1:1+N:N*N) = a
M(N+1:1+N:(N*N)-1) = d
M( 2:1+N:N*N-N) = c
As shown above a can =-k , but when I set d or c = to -k I will recieve an error.
Thank you.

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David Hill
David Hill 2020년 10월 2일
x=diag(-1:-1:-8)+diag(1:7,-1)+diag(randi(10,1,7),1);

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도움말 센터File Exchange에서 Operating on Diagonal Matrices에 대해 자세히 알아보기

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2020년 10월 2일

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2020년 10월 2일

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