"Array indices must be positive integers or logical values."

%define parameter
u= 1; %Liq velocity
D= 1; %Diffusion Coef
%domain and step
Lx= 81450; %length pipeline (m)
nx= 50; %num step in space(x)
nt= 100; %num time step
dx= Lx/(nx-1); %width space step
%satisfy CFL condition (ensure stability)
c=1; %speed
C=0.1; %Courant number (CFL condition <1)
dt= C*dx/c; %width each time step
%field variable
A = zeros(1,nx); %H2S concentration
x= linspace (0,Lx, nx); %distance
%initial condition
A(i)= 1; %conc. at initial
t=0; %at time=0
%loop
for n=1:nt
Ac= A; %save concentration into Ac for later used
t=t+dt; %new time
%new concentration
for i=2:nx-1
A(i)= Ac(i) + ((dt* D)/(dx*dx))* ((Ac(i+1)- 2*Ac(i)+ Ac(i-1)));
end
%boundary condition
A(1)=0; A(end)=0; %Dirichlet
%visualize
plot(x,A); set(gca,'ylis', [0 100]);
xlabel('Distance in pipeline'); ylabel('H2S concentration');
title(sprintf ('H2S diffusion'));
pause(0.01);
end
return;

댓글 수: 4

why there is array error and how to solve it?
Your problem is you have not defined the variable "i" when you call "A(i) = 1;". So matlab doesn't know what index in A you want set to 1.
It's not that Matlab doesn't know what i is, assuming it's not defined by the user. It's that i takes on the value of the imaginary unit when not otherwise defined.
>> clear
>> i
ans =
0 + 1i
Thank you for the explanation !

댓글을 달려면 로그인하십시오.

 채택된 답변

Adam Danz
Adam Danz 2020년 9월 24일
편집: Adam Danz 2020년 9월 24일
If this is the complete script, the error is caused in this line where i is not defined and therefore takes the default value of the imaginary unit which is not a positive integer nor a logical value.
A(i)= 1; %conc. at initial
If this is not where the error is generated, provide the entire error message and indicate which line causes the error.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Function Creation에 대해 자세히 알아보기

태그

질문:

2020년 9월 24일

댓글:

2020년 9월 24일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by