Automaticlly converting negative values to 0

Hey. This is my code.
Ex_UpperBar * Ey_UpperBar * image(x_LowerBar,y_LowerBar)
Ex_UpperBar * Ey_UpperBar
ans =
-1
image(x_LowerBar,y_LowerBar)
ans =
uint8
89
but it is giving the Answer:
Ex_UpperBar*Ey_UpperBar*image(x_LowerBar,y_LowerBar)
ans =
uint8
0
It is supposed to return -89. How do i fix it? Thanks

 채택된 답변

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2020년 5월 18일

0 개 추천

Use a command int8() or int16() to store your processed data that resolves your task. e.g.: a= -89; b=int8(a)

추가 답변 (2개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2020년 5월 18일
편집: Sulaymon Eshkabilov 2020년 5월 18일

0 개 추천

uint8 cannot store -89 and thus, 0
Thus, store your data in int8 or better int16.
Sulaymon Eshkabilov
Sulaymon Eshkabilov 2020년 5월 18일

0 개 추천

Store you data in int8 or int16

댓글 수: 2

Abad Ch
Abad Ch 2020년 5월 18일
it is in uint8 @Sulaymon Eshkabilov
int16(Ex_UpperBar)*int16(Ey_UpperBar)*int16(image(x_LowerBar,y_LowerBar))

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