how to use function "find" over matrices

Suppose x = rand(1e5,1e5);

I want to find the lowest number in each column of x without using for loop.

Is it possible?

Answer 1

[Stephen23]

"find the first value in each column which lis ess than 0.25 but greater than 0.2."

>> x = rand(13,7)
x =
   0.833676   0.654529   0.869031   0.922756   0.586565   0.278136   0.595271
   0.335144   0.936490   0.552751   0.676447   0.924786   0.813253   0.388776
   0.171351   0.992074   0.426227   0.814150   0.599205   0.378885   0.470132
   0.368957   0.162066   0.044178   0.911514   0.431260   0.111011   0.348894
   0.787866   0.150796   0.783209   0.406310   0.116503   0.232302   0.350849
   0.676606   0.782741   0.251472   0.223849   0.872576   0.665249   0.287961
   0.176415   0.750830   0.958001   0.274026   0.107420   0.716966   0.612980
   0.030644   0.103396   0.297286   0.256401   0.902245   0.486087   0.812681
   0.563573   0.414845   0.615615   0.335131   0.589437   0.396942   0.780523
   0.994748   0.314337   0.721215   0.946815   0.446822   0.252527   0.593235
   0.438298   0.516228   0.978322   0.183097   0.011558   0.731435   0.948024
   0.496606   0.172242   0.224708   0.339960   0.425773   0.730056   0.809002
   0.234744   0.195880   0.086287   0.702632   0.708232   0.489843   0.558111
>> y = x>0.2 & x<0.25;
>> [row,col] = find(y & cumsum(y,1)==1)
row =
   13
   12
    6
    5
col =
    1
    3
    4
    6

Answer 2

[David Hill]

min(x);

[parham kianian]

Let me to clarify the question.

Suppose it is aimed to find the first value in each column which lis ess than 0.25 but greater than 0.2.

How can I do that?

[David Hill]

x = rand(1e4);
a = x.*(x>.2&x<.25);
b=arrayfun(@(y)a(find(a(:,y),1),y),1:size(a,2));

[parham kianian]

Thank you David. It works well. But the method suggested by Stephen is a little easier.