Create a function called f that receives an input vector and satisfies the following criteria:
For values of x > 2, f(x) = x^2
For values of x ≤ 2, f(x) = 2x
Plot your results for values of x from –3 to 5. The plot should have a title, and both the x and y axis should be labeled.
I've got my function written and it works, but when I run it, it only plots values for when f(x)=x^2. I know I have a small mistake somewhere, and I'd appreciate if someone could help me out. Here's what I've got so far:
function y=f(x)
for i=x
if i>2
y=x.^2;
elseif i<=2
y=2*x;
end
end
xlabel 'x'
ylabel 'f(x)'
title('Unit Example 4, Problem 6')
plot(x,y,'k*')
end

 채택된 답변

David Hill
David Hill 2020년 4월 3일

0 개 추천

function y=f(x)
for i=x
if i>2
y=x.^2;%you are reassigning y every iteration, your y will be the last one
elseif i<=2
y=2*x;
end
end
xlabel 'x'
ylabel 'f(x)'
title('Unit Exam 4, Problem 6')
plot(x,y,'k*')
end
It is actually much easier without a for-loop.
function y=f(x)
y=zeros(size(x));
y(x>2)=x(x>2).^2;
y(x<=2)=x(x<=2)*2;
xlabel 'x'
ylabel 'f(x)'
title('Unit Exam 4, Problem 6')
plot(x,y,'k*')
end

댓글 수: 2

Your funtion works properly and shows the correct values and figure, but question I posted is intending on the user utililzing for/while loops.
function y=f(x)
for i=1:length(x)
if x(i)>2
y(i)=x(i)^2;
else
y(i)=2*x(i);
end
end
xlabel 'x'
ylabel 'f(x)'
title('Unit Exam 4, Problem 6')
plot(x,y,'k*')
end

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Programming에 대해 자세히 알아보기

제품

릴리스

R2020a

질문:

2020년 4월 2일

댓글:

2020년 4월 3일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by