I am trying to write and test a function to determine whether a person is old enough to drink or not (with the legal age being 19).
For some reason when I test the function the code will run but not display the message that I set. How can I fix this code so that it will display the proper message?
FUNCTION:
function[ans] = drink(age)
if(age<19)
ans = 'no';
else
ans = 'yes';
end
TESTING:
clear
clc
addpath('Library')
age = input('Enter your age: ' );
ans = drink(age);
if(ans == strcmpi(ans, 'yes'))
disp('Old enough to drink')
elseif(ans == strcmpi(ans, 'no'))
disp('Not old enough to drink')
end

댓글 수: 1

Adam
Adam 2019년 12월 9일
편집: Adam 2019년 12월 9일
Don't call variables 'ans', for starters. Also, this 'logic' is really confusing:
if(ans == strcmpi(ans, 'yes'))
...
end
Just
if( strcmp( result, 'yes' ) )
should work fine. It seems a bit odd though that you put logic in your function to return 'yes' or 'no', then more logic that effectively checks the same thing to the convert to a different string!

댓글을 달려면 로그인하십시오.

 채택된 답변

Star Strider
Star Strider 2019년 12월 9일

0 개 추천

First, it is best not to use ‘ans’ as a variable, since it is the default variable and can be overwritten.
Second, the the if and elseif conditions were not coded correctly.
This works:
if strcmpi(rsp, 'yes')
disp('Old enough to drink')
elseif strcmpi(rsp, 'no')
disp('Not old enough to drink')
end

댓글 수: 2

Alicia Sood
Alicia Sood 2019년 12월 9일
Noted, thank you!
Star Strider
Star Strider 2019년 12월 9일
As always, my pleasure!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터 및 File Exchange에서 Testing Frameworks에 대해 자세히 알아보기

질문:

2019년 12월 9일

댓글:

2019년 12월 9일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by