Find indices of points in meshgrid-like data

조회 수: 43 (최근 30일)
Aleksander Marek
Aleksander Marek 2018년 9월 26일
댓글: Aleksander Marek 2018년 9월 27일
Hi,
I'm looking for an optimal solution to the following problem:
You are given a vector containing coordinates x,y for set of points e.g.:
A = [2 3; 3 4; 1 1];
given that the full-data is structured in a matrix form (meshgrid-like)
[X,Y] = meshgrid(1:5, 1:5);
find indices B, such that:
A = [X(B), Y(B)];
I am able to solve this problem simply by looping over all points in A and finding the index with
for pt = 1:size(A,1);
index(pt) = find(A(pt,1)== X & A(pt,2) == Y);
end
However I'm not satisfied with the performance of this solution as I am running through ~50,000 data points around 300 times, and I'd love to replace the for loop with some vectorized formula.
Any help would be highly appreciated!
Thanks,
Alex

채택된 답변

Adam
Adam 2018년 9월 26일
[~, index] = ismember( A, [X(:) Y(:)], 'rows' );
Not sure if that is any faster than a loop though. ismember is not a very performant function as, if I remember correctly, it contains quite a lot of checks that slow it down.
  댓글 수: 1
Aleksander Marek
Aleksander Marek 2018년 9월 27일
It actually works really well, and gives improvement of about 10 times over the for loop.
Thanks a lot!

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추가 답변 (1개)

Bish Erbas
Bish Erbas 2018년 9월 26일
How about this?
A = [2 3; 3 4; 1 1];
[X,Y] = meshgrid(1:5, 1:5);
XIdxCell = arrayfun(@(x) find(X==x),A(:,1),'UniformOutput',false);
YIdxCell = arrayfun(@(x) find(Y==x),A(:,2),'UniformOutput',false);
XIdx = cell2mat(XIdxCell);
YIdx = cell2mat(YIdxCell);
A = [X(XIdx), Y(YIdx)]

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