Count how many times a number is repeated in a certain row of an array

조회 수: 40 (최근 30일)
Please consider the array
A = [1;1;1;2;2;2;2;2;3;3;4;4;4;4;4;4;4;5;5;5;5];
I would like to determine how many times each number repeats.
For 1, it repeats three times. For 2, it repeats five times, and so on.
If there is other data in columns to the left of the array A that does not follow the same repeating pattern, can I still count how many times each number in a certain column is repeated?
  댓글 수: 2
Adam
Adam 2018년 7월 20일
doc histcounts
would be one way of doing it, depending on how many unique values you are likely to have, though however many there are you could use that many bins.
NSHh
NSHh 2021년 5월 15일
이동: DGM 2024년 7월 20일
am wondering as well

댓글을 달려면 로그인하십시오.

채택된 답변

Aquatris
Aquatris 2018년 7월 20일
Here is a code;
A = [1;1;1;2;2;2;2;2;3;3;4;4;4;4;4;4;4;5;5;5;5];
c = unique(A); % the unique values in the A (1,2,3,4,5)
for i = 1:length(c)
counts(i,1) = sum(A==c(i)); % number of times each unique value is repeated
end
% c(1) is repated count(1) times
  댓글 수: 16
Aquatris
Aquatris 2020년 5월 5일
From the above example, the code can be (for relatively newer versions of Matlab;
d = c(counts<4);
where d has the value that appear less than 4 times in the A vector. Alternatively;
I = find(counts<4); % find indices where counts variable elements are less than 4
d=c(I);
PEDRO ALEXANDRE Fernandes
PEDRO ALEXANDRE Fernandes 2022년 3월 4일
Hi. I have a similar problem. if i have a multidimensional array of the style 7 X 10
9 5 2 1 5 3 3
1 8 3 1 7 4 3
1 3 1 1 8 6 4
1 3 1 6 4 2 1
2 1 6 3 2 2 1
2 3 1 1 7 5 4
1 1 4 2 1 8 6
Columns 8 through 10
2 2 5
2 2 6
4 2 4
2 9 7
1 9 1
2 1 5
5 4 5
and I intend to count the number of times each digit appears per line.
Example: on line 1
1 -> 1
2 -> 3
3 -> 2
..
and then the same in the following lines. Any idea?

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

태그

제품


릴리스

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by