Most efficient way to generate an array around a central value
이전 댓글 표시
Hi!
I am trying to span a linearly spaced array around a center value without knowing number of points in the array beforehand. I only have the step size and the lower and upper limits that must not be exceeded. For example, if center = -4,3, stepsize = 2, lower = -7, upper = 3, then the resulting array should be array = [-6.3 -4.3 -2.3 -0.3 1.7].
Is there a way to generate such an array as efficiently as possible (e.g. without while-loops)?
Thanks for all the help in advance!
채택된 답변
추가 답변 (1개)
[ flip( center:-stepsize:lower ), ( center + stepsize ):stepsize:upper ];
looks like it would work, though I haven't tested all edge cases and there are probably neater ways.
If you prefer you could just do the simpler:
unique( [ flip( center:-stepsize:lower ), center:stepsize:upper ] );
to get rid of the duplicated centre point, though I imagine it is less efficient.
카테고리
도움말 센터 및 File Exchange에서 Logical에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!