speed up the & operation
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How to speed up the following code? I did profiling, and this line takes 3267.72s for calling 245913489 times.
a=[1 0 1 1 0 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1];
b=[1 0 1 1 0 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0];
for i=1:1000000
aat=((a(1,1:24)==0)&(b(1,25:48)==1)&(~ismembc(1:24,5:50)))';
end
댓글 수: 5
Walter Roberson
2018년 4월 13일
for i=1:1000000
part1 = a(1,1:24)==0;
part2 = b(1,25:48)==1;
part3 = ~ismembc(1:24,5:50);
part4 = part1 & part2 & part3;
aat = part4 .';
end
Now when you profile you can see exactly which part of the expression is taking the most time.
We suspect that it is the ismembc() that is taking all of the time and that the & is relatively fast.
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