How to shift x axis to origin?

x= linspace(0,6*180,1000);
y1 = sind(x);
y2 = sind(x-120);
y3 = sind(x-240);
plot(x,y1,x,y2,x,y3)
ax = gca;
ax.XLim = [0 4*180]
ax.XTick = [0 180 2*180 3*180 4*180]
ax.XAxisLocation = 'origin';
THIS CODE IS NOT WORKING

[Adam]

There's no point just saying something is 'not working' if you don't explain why. Both axes in that plot appear to be at the origin to me when I run the code.

[Jos (10584)]

When I execute your code above in R2017b, I get the following error:

Undefined function or variable 'THIS'.

[Jan]

@Jos: Did you copy and paste "THIS CODE IS NOT WORKING" also?

[Ankit kumar]

No.

[Jos (10584)]

@jan: yep :p (silly joke, I'll admit it ...)

Answer 1

[Steven Lord]

If the error you receive is that 'origin' is not a valid or recognized value for the XAxisLocation property, you may be using a release older than release R2015b which is when that value was added as an option for the XAxisLocation property. Prior to that the only allowed options were 'top' and 'bottom'.

If you received a different error, or did not receive an error but did not receive the behavior you expected, tell us what release you're using and describe in detail (including any error or warning messages you received, all the text in red or orange) what happened.

One more point: I would be careful about using gca in my code. A user of that code, clicking on a different axes in a different figure between the plot call and the line that creates the variable ax, could change what the current axes is and so make gca return something other than what you expect.

[Ankit kumar]

I am using R2015 version.My code is working fine but only x axis is not shifted to origin.

[Steven Lord]

Use print to print the figure window to an image file then insert that image into a comment on this question using the button that looks like a green object inside a brown frame.

Answer 2

[KSSV]

Try this: https://in.mathworks.com/matlabcentral/fileexchange/10473-plotaxisatorigin