Finding specfic string within another string
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I am having trouble finding a specific part of a file path. The path is something along: \\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST
I need to find "04 - Black" in the path name. The name is changing and so is its position in the path - Therefor I need to find the first instance of 'XX - '. Afterwards I need to find the "05 - TEST" folder, which is also changing name and position.
Can anyone help?
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답변(5개)
José-Luis
2017년 9월 18일
yourStr = '\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST'
re = '\\[0-9]{2}\s-\s[a-zA-Z]+';
result = regexp(yourStr,re,'match');
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Guillaume
2017년 9월 18일
Other possible regex, which is more permissive:
re = '\\[0-9]{2}\s-\s[^\\]+';
Allows anything that is not \ after the two digits, whitespaces, and dash.
Guillaume
2017년 9월 18일
if the aim is to obtain the name of the folder after the 'XX - ', then:
folder = regexp(path, '(?<=\\[0-9]{2}\s-\s[^\\]+\\)[^\\]+', 'match', 'once')
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Cedric Wannaz
2017년 9월 18일
Why not simply
>> str = '\\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST' ;
>> folders = regexp( str, '\d\d - [^\\]+', 'match' )
folders =
1×2 cell array
'04 - Black' '05 - TEST'
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Cedric Wannaz
2017년 10월 8일
편집: Cedric Wannaz
2017년 10월 8일
Yes but we need to match a sub-string in this context and for this he needs to use the correct separator in the pattern, for REGEXP to work. He could use both for ending the match by defining the pattern as '\d\d - [^\\/]+'.
But again, if there is no problem in the "other direction" (because MATLAB can deal with either filesep), here both possibilities have to be managed, either by building the pattern using filesep or by making the pattern flexible enough.
Lucas Silva
2018년 11월 26일
Eu tenho que fazer um processo semelhante, mas o método de separar as seqüências de caracteres é o ';' Eu tentei identificar o; como se fosse parte do comando, mas o matlab não aceita como.
Existe alguma maneira de obter essa informação?
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