How to get the smallest difference(Array)
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>>The issue i'm having is that if there are two values of equal difference only the closest one is displayed. Can someone please correct my coding.
function[smallestPosition] = FindSmallestElevationChange(i,B)
E = [ 3 6 5 4 7 8 3 ; 5 7 6 2 3 1 7 ; 6 8 5 8 5 4 8 ; 7 4 9 7 6 5 3 ];
*%B = 3 adjacent values e.g.. if I chose E(10), B = [ 4 2 8 ]
%the smallest difference should be 4 and 8 which is (1 and 3) respectively
%since there is a difference of 2 for both of them.*
E(i);
[c index] = min(abs(B-E(i)));
the output given is only 1(which is 4)
[REVERTED, was edited away by the OP, Jan]
댓글 수: 7
Cedric
2017년 9월 17일
편집: Cedric
2017년 9월 17일
Shivam Prasad, the least you can do if you don't need help anymore, is to accept the answer of whoever was nice enough to give you freely part of his/her time.
I accepted the answer from José-Luis (before Jan restored the original question and answered).
The question was originally titled "How to get the smallest difference(Array)" and it had the following picture attached:
채택된 답변
José-Luis
2017년 8월 31일
bla = randi(50,10);
val = 25;
result = abs(bla-val);
result = result == min(result(:));
[xx,yy] = ndgrid(1:size(bla,1),1:size(bla,2));
idx_x = xx(result)
idx_y = yy(result)
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추가 답변 (1개)
Jan
2017년 9월 17일
편집: Jan
2017년 9월 17일
The question does not contain the detail, that the input is a matrix, but a scalar and a vector only. Then:
[c, index] = min(abs(Vec - E));
is almost a solution. Do it in two steps:
Dist = abs(Vec - E);
and then use this to determine the indices:
Dist == min(Dist)
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