>>The issue i'm having is that if there are two values of equal difference only the closest one is displayed. Can someone please correct my coding.
function[smallestPosition] = FindSmallestElevationChange(i,B)
E = [ 3 6 5 4 7 8 3 ; 5 7 6 2 3 1 7 ; 6 8 5 8 5 4 8 ; 7 4 9 7 6 5 3 ];
*%B = 3 adjacent values e.g.. if I chose E(10), B = [ 4 2 8 ]
%the smallest difference should be 4 and 8 which is (1 and 3) respectively
%since there is a difference of 2 for both of them.*
E(i);
[c index] = min(abs(B-E(i)));
the output given is only 1(which is 4)
[REVERTED, was edited away by the OP, Jan]

댓글 수: 7

KSSV
KSSV 2017년 8월 31일
Please not that....._min_ gives you only minimum value....so output is only one value. What you are expecting?
KL
KL 2017년 8월 31일
What's the point of uploading that picture? You expect us to read it this way?
José-Luis
José-Luis 2017년 8월 31일
Where on god's green earth is abs(10-8) equal to abs(10-4)?
Let me rephrase. Unless something very basic has changed, there is no way that
2 == 4
You probably meant E(6) (just dawned on me, I need coffee). If that's the case, my answer should solve your problem.
José-Luis
José-Luis 2017년 8월 31일
Well then I don't understand what you are trying to achieve.
Cedric
Cedric 2017년 9월 17일
편집: Cedric 2017년 9월 17일
Shivam Prasad, the least you can do if you don't need help anymore, is to accept the answer of whoever was nice enough to give you freely part of his/her time.
I accepted the answer from José-Luis (before Jan restored the original question and answered).
The question was originally titled "How to get the smallest difference(Array)" and it had the following picture attached:
Jan
Jan 2017년 9월 17일
편집: Jan 2017년 9월 17일
I have reverted the question. Please, Shivam Prasad, do not remove the question after somebody has spent the time to provide an answer.

댓글을 달려면 로그인하십시오.

 채택된 답변

José-Luis
José-Luis 2017년 8월 31일

0 개 추천

bla = randi(50,10);
val = 25;
result = abs(bla-val);
result = result == min(result(:));
[xx,yy] = ndgrid(1:size(bla,1),1:size(bla,2));
idx_x = xx(result)
idx_y = yy(result)

추가 답변 (1개)

Jan
Jan 2017년 9월 17일
편집: Jan 2017년 9월 17일

1 개 추천

The question does not contain the detail, that the input is a matrix, but a scalar and a vector only. Then:
[c, index] = min(abs(Vec - E));
is almost a solution. Do it in two steps:
Dist = abs(Vec - E);
and then use this to determine the indices:
Dist == min(Dist)

카테고리

도움말 센터File Exchange에서 Image Processing Toolbox에 대해 자세히 알아보기

제품

질문:

2017년 8월 31일

편집:

2017년 9월 17일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by