Loop to extract rows from matrix

조회 수: 3 (최근 30일)
GiuBa
GiuBa 2017년 8월 29일
편집: Jan 2017년 8월 30일
Hi, I need to extract each rows of a matrix creating different variables. How a can do it? Thanks in advance!

채택된 답변

Jan
Jan 2017년 8월 29일
The dynamic creation of a bunch of vectors causes troubles. It is even worse, if you want to use these vectors later on. To access a column of a matrix, simply use an index: A(:, i) is the i.th column. This is fast, clean and simple.
Please explain, why you assume that creating a set of variables is useful in your case. I'm sure, that the forum can give you better options to solve the actual problem.
  댓글 수: 3
Adam
Adam 2017년 8월 30일
Why can't you just create the text files from the one initial array, taking a row at a time?
Jan
Jan 2017년 8월 30일
편집: Jan 2017년 8월 30일
Again: No, you do not need to create the vectors explicitly. Trying to do so is a shot in your knee. A(iRow, :) is perfect already.
Do you want to create 228 files? Then:
hdr = {'a ','b','c'}; % First header%
hdr2 = {'(m)','(%)','(%)'}; % Second Header%
fmt = repmat('%s\t ', 1, length(hdr));
fmt(end:end+1) = '\n';
for iRow = 1:size(A, 1);
fnam = sprintf('test%03d.txt', iRow);
fid = fopen(fnam, 'w');
fprintf(fid, fmt, hdr{:});
fprintf(fid, fmt, hdr2{:});
fclose(fid);
dlmwrite(fnam, A(iRow, :), '-append', 'delimiter', '\t');
end
This can be done directly also without dlmwrite:
fmtData = [repmat('%g\t', 1, size(A, 2) - 1), '%g\n'];
...
fprintf(fid, fmt, hdr2{:});
fprintf(fid, fmtData, A(iRow, :));
fclose(fid);
end

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Data Types에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by