Subplot function interfering with appropriate plot display
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When I try to use subplot to show impulse response and unit step response in the same figure, the impulse response plot displays incorrectly. Any idea why subplot is not plotting both the impulse response and unit step response appropriately? Uncomment the second section of code to see the problem. Thanks!
a = [1,-1,0.9];
b = [1];
n = [-20:120];
h = impz(b,a,n);
subplot(1,2,1); stem(n,h);
title('Impulse response'); xlabel('n'); ylabel('h(n)');
% %Plot unit step response ex. 2.11 b
% x = stepseq(0,-20,120);
% a1 = [1,-1,0.9]; b1 = [1];
% s = filter(b1,a1,x);
% n1 = [-20:120];
% subplot(1,2,2); stem(n1,s);
% title('Step response'); xlabel('n'); ylabel('s(n)');
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채택된 답변
Star Strider
2017년 8월 23일
The impulse and step responses are defined as beginning from 0, and do not exist for negative time. I can’t find ‘stepseq’ in the online documentation.
This works:
a = [1,-1,0.9];
b = [1];
n = [-20:120];
[h,t] = impz(b,a,n);
subplot(1,2,1); stem(t,h);
title('Impulse response'); xlabel('n'); ylabel('h(n)');
%Plot unit step response ex. 2.11 b
% x = stepseq(0,-20,120);
a1 = [1,-1,0.9]; b1 = [1];
s = stepz(b1,a1,120);
n1 = [-20:120];
subplot(1,2,2); stem(n1',[zeros(21,1); s]);
title('Step response'); xlabel('n'); ylabel('s(n)');
I would also stack them vertically rather than plot them horizontally, so use subplot(2,1,1) and subplot(2,1,2) instead.
추가 답변 (1개)
Siambou Camara
2019년 9월 16일
A well-known discontinuous function is impulse function that is defined as: δ(t) = 1 t = 0 0 otherwise. (1) In order to generate impulse function using matlab, follow the same steps as previous section, but this time using the following Matlab code.
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