Matlab workers in Parloop are not using the path order

조회 수: 5 (최근 30일)
Leandro
Leandro 2017년 1월 25일
댓글: Adam 2018년 2월 2일
Hello, I'm using this code
parfor k=1:10
[..]=pca(..)
end
I have 2 definitions of pca (the matlab package and another package). I've set the search path to use the matlab package by default, but inside the parloop the other function is used instead. I didn't found a way to arrange this without removing the other package. Thanks
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Leandro
Leandro 2017년 1월 26일
I could do that, but it can be troubleosome. For instance, pca is an internal function in the package, so I have to change several lines, and the package is from a third party.
I modidify the path through the desktop app (not in code).
Adam
Adam 2018년 2월 2일
I would have thought if one of them was in a package that you would have to specify it with the package name prepended, which would remove the ambiguity anyway.

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Edric Ellis
Edric Ellis 2017년 1월 26일
This appears to be a problem with the automatic path mirroring that is used when setting up a parallel pool. Things work correctly if you modify the client MATLAB path only after creating the parallel pool.
  댓글 수: 2
Leandro
Leandro 2017년 1월 26일
Thank you! Indeed a strage bug, becouse you can set path priorities in the IDE, so it should be mirrored in the same way.
Thomas Pfau
Thomas Pfau 2018년 2월 2일
But which path is matlab using then? I have a very similar situation:
2 Toolboxes, both have the same function name. In our code we dynamically change the path depending on which of the toolboxes is required. However, as soon as there is a parfor loop, we are in trouble, as the path seems to be ignoring anything we do before.
  • Changing the path before the pool is created -> No Effect
  • Changing the path after the pool is created -> No Effect.
The only thing I see is to change the path in the parfor loop, but this (at least in our case) would create an overhead that would make parfor pointless.
I'm really wondering, whether there is any way to manipulate the path of a cluster or how the cluster determines its path.

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