concatonate time axis using a loop

I have a time axis which keeps resetting due to drop outs in the logging e.g.

t = 0,1,2,3,4,5,0,1,2,3,4,5,6,7,8,9,10,0,1,2,3,4,5,6,7,8,9,10,0,1,2 and so on....

What is the most efficient piece of code to generate the new time vector so that the zeros continue on from the last time value before the dropout.

t = 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30

Thanks!

Jordan.

[Adam]

I assume your real problem is a little more complex than the example you posted because to get that time vector you can just do

t = 0:numel(t) - 1;

Answer 1

[Marc Jakobi]

This should do it:

t = [0,1,2,3,4,5,0,1,2,3,4,5,6,7,8,9,10,0,1,2,3,4,5,6,7,8,9,10,0,1,2];
idx = find(ismember(t, 0));
for i = 2:length(idx)-1
    t(idx(i):idx(i+1) - 1) = t(idx(i):idx(i+1) - 1) + idx(i) - 1;
end
t(idx(end):end) = t(idx(end):end) + idx(end) - 1;

[Jordan Gallacher]

Hi Marc,

Thanks! What about if the zero was not exactly zero and say 4 microseconds i.e. just a value less than the last time value before the logging reset?

Thanks,

Jordan.

[Marc Jakobi]

Then I would I would replace

idx = find(ismember(t, 0));

with

idx = find([0, diff(t)] <= 0);