how to find the column number of first zero element of each row

조회 수: 12 (최근 30일)
Jason
Jason 2016년 2월 19일
편집: Sunetra CV 2019년 11월 14일
Hi,all. could you please tell me how to find the column number of first zero element of each row. eg. for the matrix in the picture, I want the output will be outputmatrix=[3;4;4;5;5;6;6;6;6;6;1;1;1;1;1]. Thank you!

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MHN
MHN 2016년 2월 19일
편집: MHN 2016년 2월 19일
This is your answer:
a =[ -1 3 0 0 0 0
2 3 4 5 0 0
1 2 1 0 0 0]
b = abs(a); % it is a trick which forces min to do not consider your negative numbers as minimum
[~,ind] = min(b')
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MHN
MHN 2016년 2월 19일
편집: MHN 2016년 2월 19일
So, for your matrix it is just one line code:
[~,ind] = (min((abs(SumofSet1))'))
Jason
Jason 2016년 2월 19일
thank you very much!

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추가 답변 (2개)

Adam
Adam 2016년 2월 19일
편집: Adam 2016년 2월 19일
sum( abs( cumprod( yourMatrix, 2 ) ) > 0, 2 ) + 1;
should work I think. I tested in on a small matrix I made and it seems to give the correct answer. There may be simpler methods though!
The logic behind it is as follows:
  • cumprod is the cumulative product, run along each row (dimension 2) which will always be 0 for values after the first 0, hence the result of this will be a matrix in which only the elements before the first 0 on a row will be non-zero.
  • abs will ensure that all non-zero elements are positive in order for the following check to work correctly.
  • taking the sum of all the elements greater than 0 will give you the index of the last non-zero element.
  • Adding 1 at the end will give the element of the first 0 which should always be the column immediately after the last non-zero.
If need be you can use a small tolerance e.g. 1e-6 to hard set elements below that absolute tolerance to 0 before doing this as values that are not precisely 0 will likely cause problems.
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Jason
Jason 2016년 2월 19일
Thank you,but the result is not the same as i wanted. I didn't understand why you use 'sum' function here. because the element in matrix is very small, use 'cumsum' may cause the inaccuracy of the results.
Walter Roberson
Walter Roberson 2016년 2월 19일
sum(cumprod(~YourMatrix, 2), 2) + 1
Note: this will be incorrect / misleading for any row for which there is no 0 (in which case no desired result has been defined by the poster)

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Sunetra CV
Sunetra CV 2019년 11월 14일
편집: Sunetra CV 2019년 11월 14일
will this work if all the elements of my matrix are decimals?

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