how to convert a 3D surface into a 2D contour?

조회 수: 22 (최근 30일)
Ramina
Ramina 2024년 1월 27일
답변: Sulaymon Eshkabilov 2024년 1월 28일
Hi,
I have a 3D surface(download: https://uploadkon.ir/uploads/9ced27_24input.zip) and I want to convert it into a 2D contour like the image below. but I dont know how.
ps: the colorbar in the 2D plot shows the variation of y-axis in the 3D plot.
  댓글 수: 1
Torsten
Torsten 2024년 1월 27일
I'd just change the view to be frontal on the xz-plane when plotting the surface :-)

댓글을 달려면 로그인하십시오.

답변 (2개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2024년 1월 27일
This is how it can be done:
H = openfig('ds2.fig'); % This is the extracted plot figure
h = findobj(gca, 'Type', 'surface');
X = get(h, 'XData'); % Extract XData
Y = get(h, 'YData'); % Extract YData
Z = get(h, 'ZData'); % Extract YData
figure
plot(X, Z)
plot(X, Z)
xlabel("X")
ylabel("Z")
grid on
  댓글 수: 1
Ramina
Ramina 2024년 1월 28일
편집: Ramina 2024년 1월 28일
Hi, thank you for the time you took to answer my question.
I want to show the collors (like the 2D plot in my question) as well to show the variation of y-axis. Can you help me to do that as well?
Here is the code I wanted to use, but it shows this error:
Error using contourf
Z must be at least a 2x2 matrix.
Error in contour_2D (line 4)
[~, hc] = contourf(h.XData, h.ZData, h.YData);
uiopen('fig adress',1)
h = findobj(gcf,'type','surface')
figure
[~, hc] = contourf(h.XData, h.ZData, h.YData);
h2=colorbar;

댓글을 달려면 로그인하십시오.


Sulaymon Eshkabilov
Sulaymon Eshkabilov 2024년 1월 28일
Note that it is clear from the colorbar scale (Figure 2 in your question) that there must be another operation before obtaining the plot (Figure 2 in your question) that is missing in your question.
Anyhow, here is another way of getting a similar plot.
H = openfig('ds2.fig'); % This is the extracted plot figure
view(360,0)
xlabel("X")
zlabel("Z")
grid on
xlim([0, 2])

카테고리

Help CenterFile Exchange에서 Contour Plots에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by