??? Error using ==> eq Matrix dimensions must agree

[row, column]=find(My_matrix== pnode); I try to use this command and i get this error
??? Error using ==> eq Matrix dimensions must agree
What should i do?How i should write the syntaxis of it?

댓글 수: 3

Adam
Adam 2015년 4월 15일
What are the dimensions of My_matrix and pnode? I assume they are not the same size since you get that error and in that case it is impossible for any of us to know what your intention is in trying to test equality between them just from the information you have given.
pnode is a variable and it has a value and the matrix has dimensions 10X14,this is why it is weird
Actually the previous orders are min_cost = min(x(:)); [pnode, node] = find(x == min_cost); [row, column]=find(My_matrix == pnode); [rows, columns]=find(My_matrix==node);
and the min_cost instead of taking one value it takes an array

댓글을 달려면 로그인하십시오.

답변 (1개)

John D'Errico
John D'Errico 2015년 4월 15일
편집: John D'Errico 2015년 4월 15일

0 개 추천

Your matrices are not compatible in size. READ THE ERROR MESSAGE!
Try this:
whos MY_matrix pnode
What does it tell you?

댓글 수: 3

The weird is that pnode is a variable with a single value,it isnt a matrix nor an array
Giannakis Stoukas
Giannakis Stoukas 2015년 4월 15일
편집: John D'Errico 2015년 4월 15일
Actually the previous orders are
min_cost = min(x(:));
[pnode, node] = find(x == min_cost);
[row, column]=find(My_matrix == pnode);
[rows, columns]=find(My_matrix==node);
and the min_cost instead of taking one value it takes an array
I see that the last line has
find(My_matrix==node);
Even if pnode is a scalar, node may well not be so, since it was created from a previous call to find.

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Statistics and Machine Learning Toolbox에 대해 자세히 알아보기

태그

질문:

2015년 4월 15일

댓글:

2015년 4월 15일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by