Assisted Simplification with other equations?

조회 수: 3 (최근 30일)
Ali Almakhmari
Ali Almakhmari 2023년 10월 10일
댓글: Ali Almakhmari 2023년 10월 11일
I want to simplify an equation knowing certain other information. My equation is this:
syms b Q e gamma K_phi eta K_theta ao CL_delta delta_o CM_delta c ao
eqn = (ao*((CL_delta*Q)/ao - (Q^2*e*(tan(eta)*((CL_delta/ao + (CM_delta*c)/(ao*e))*((Q*b)/2 - cos(gamma)*sin(gamma)*(K_phi - K_theta)) + (CL_delta*b*(K_theta*cos(gamma)^2 - Q*e + K_phi*sin(gamma)^2))/(2*ao*e)) - (CL_delta/ao + (CM_delta*c)/(ao*e))*(K_phi*cos(gamma)^2 + K_theta*sin(gamma)^2 + (Q*b*tan(eta))/2) + (CL_delta*b*(cos(gamma)*sin(gamma)*(K_phi - K_theta) + Q*e*tan(eta)))/(2*ao*e)))/((K_phi*cos(gamma)^2 + K_theta*sin(gamma)^2 + (Q*b*tan(eta))/2)*(K_theta*cos(gamma)^2 - Q*e + K_phi*sin(gamma)^2) + (cos(gamma)*sin(gamma)*(K_phi - K_theta) + Q*e*tan(eta))*((Q*b)/2 - cos(gamma)*sin(gamma)*(K_phi - K_theta)))))/(CL_delta*Q);
I was told that using the below information that I can simplify eqn to be truely a function of gamma alone, but I cannot prove it or do it in MATLAB. The info is:
b/c = 6;
e/c = 0.1;
K_phi/K_theta = 3;
CL_delta/ao = 0.4805020381;
CM_delta/ao = -0.096610459;
eta = pi/6;

채택된 답변

Torsten
Torsten 2023년 10월 10일
이동: Walter Roberson 2023년 10월 11일
I was told that using the below information that I can simplify eqn to be truely a function of gamma alone
Since Q does not appear in your 6 conditions, this cannot be true.
  댓글 수: 1
Walter Roberson
Walter Roberson 2023년 10월 11일
... Unless Q happens to appear in a way that cancels once you do the other substitutions. Which does not happen to be the case. The Q^2 in the numerator can be divided by the Q in the denominator, but that is going to leave a Q.

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추가 답변 (1개)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023년 10월 10일
Use subs() command and assign variables properly, e.g.:
syms b Q e gamma K_phi eta K_theta ao CL_delta delta_o CM_delta c ao
eqn = (ao*((CL_delta*Q)/ao - (Q^2*e*(tan(eta)*((CL_delta/ao + (CM_delta*c)/(ao*e))*((Q*b)/2 - cos(gamma)*sin(gamma)*(K_phi - K_theta)) + (CL_delta*b*(K_theta*cos(gamma)^2 - Q*e + K_phi*sin(gamma)^2))/(2*ao*e)) - (CL_delta/ao + (CM_delta*c)/(ao*e))*(K_phi*cos(gamma)^2 + K_theta*sin(gamma)^2 + (Q*b*tan(eta))/2) + (CL_delta*b*(cos(gamma)*sin(gamma)*(K_phi - K_theta) + Q*e*tan(eta)))/(2*ao*e)))/((K_phi*cos(gamma)^2 + K_theta*sin(gamma)^2 + (Q*b*tan(eta))/2)*(K_theta*cos(gamma)^2 - Q*e + K_phi*sin(gamma)^2) + (cos(gamma)*sin(gamma)*(K_phi - K_theta) + Q*e*tan(eta))*((Q*b)/2 - cos(gamma)*sin(gamma)*(K_phi - K_theta)))))/(CL_delta*Q);
display(eqn)
eqn = 
b = 6*c;
e = 0.1*c;
K_phi = 3*K_theta;
CL_delta = 0.4805020381*ao;
CM_delta = -0.096610459*ao;
eta = pi/6;
eqn=subs(eqn, b);
eqn=subs(eqn, e);
eqn=subs(eqn, K_phi);
eqn=subs(eqn, CL_delta);
eqn=subs(eqn, CM_delta);
eqn=subs(eqn, eta);
FINAL_eqn = eqn;
display(FINAL_eqn)
FINAL_eqn = 
  댓글 수: 2
Walter Roberson
Walter Roberson 2023년 10월 11일
This is not going to be able to transform to an expression in just gamma. This is not the correct solution to the question asked, and Torsten had the correct answer.
Ali Almakhmari
Ali Almakhmari 2023년 10월 11일
Thank you both, I realized my mistake in the original expression and this command definitely will work for me.

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