how do i store mutiple txt files into a 3d matrix

hi!,
im a highschool student whos very new to matlab and ive been assighned this task to store 3000 text files into one 3d matrix using the for loop command. I have no idea what im doing so any help is much appreciated!

댓글 수: 3

dpb
dpb 2022년 8월 10일
What is the content of each text file for starters...one presumes they are 2D arrays? It would be a pretty common (and handy) storage arrangment in MATLAB to place each 2D array as a plane in a 3D array.
That should provide some hints... :)
Good luck, give it a go and post back your efforts with specific Q? where you run into a specific problem. There's an <FAQ#How_can_I_process_a_sequence_of_files?> that you may find of benefit.
I'd note that hopefully the files have been named such that a wild card file specification with dir will give you the list of files over which to loop -- it's by far the simplest technique.
hey! i took some help from a friend and they told me to use this code, but my issue with thise code is that only the first frame is loaded properly and the rest when loaded are loaded as zeros and not with the numbers in the original text frame. My frames are 2D with just a ton of numbers and there are 3000 of them, how do i fix this issue?
Matrix=zeros(156,207,3000);
for i = 1:3000
Matrix(:,:,1)=load(['frames_' num2str(i-1) '.txt']);
end
Stephen23
Stephen23 2022년 8월 16일
편집: Stephen23 2022년 8월 16일
@tina: you changed the original indexing into a 1, which is why you only store the first frame.
N = 3000;
M = nan(156,207,N);
for ii = 1:N
F = sprintf('frames_%d.txt',ii-1);
M(:,:,ii) = readmatrix(F);
end % ^^ compare this indexing

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답변 (1개)

David Hill
David Hill 2022년 8월 16일
Matrix=zeros(156,207,3000);
for i = 1:3000
Matrix(:,:,i)=readmatrix(['frames_' num2str(i-1) '.txt']);
end

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질문:

2022년 8월 10일

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2022년 8월 16일

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