Generate specific shape randomly using MATLAB
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Hello every one, I hope you are doing well
i have the following code,in which i have two thing. first is the val in which i have the value like 200 is the value and it repeat 120 times to complete the shape.
I want to do it randomly , like the value generate randomly between 1 to 1000 and num is also randomly between 1 to 500 . How can i generate it in MATLAB
val = [200,500,800,1000,800,900,700,300,600,150];
num = [120,400,200,400,300,450,200,400,500,400];
out4 = repelem(val,num);
scatter(1:length(out4),out4)
댓글 수: 1
David Hill
2022년 3월 6일
Your explaination is not clear to me. A short example would be helpful.
답변 (2개)
Image Analyst
2022년 3월 6일
To generate fractional random numbers use rand(). To generate random integers use randi().
randomDoubles = 999 * rand(1, length(val)) + 1; % Between 1 and 1000
randomIntegers = randi([1, 500], 1, length(num)); % Between 1 and 500
Not sure what else you need to know beyond that. If you need something else, be very explicit and specific.
Image Analyst
2022년 3월 6일
Try this:
val = unique(sort(20 * randi(50, 10, 1)))
for k = 1 : length(val)
y = val(k);
num1 = randi(3500);
num2 = randi(4000);
plot([num1, num2], [y, y], 'b.-', 'LineWidth', 5, 'markerSize', 20)
hold on;
end
grid on

댓글 수: 10
Med Future
2022년 3월 6일
Med Future
2022년 3월 6일
Image Analyst
2022년 3월 6일
I plotted that because that's what you said you wanted: "Like the picture below . i want to generate this shape with random values ."
How many elements do you want there to be between the left endpoint of the line segment and the right endpoint? You can use
numVec = linspace(num1, num2, numberOfElements);
A good investment of your time:
Med Future
2022년 3월 6일
Med Future
2022년 3월 6일
Image Analyst
2022년 3월 6일
Again, "How many elements do you want there to be between the left endpoint of the line segment and the right endpoint?"
And do you want each value of val to be in its own row? Or maybe you want this:
val = unique(sort(20 * randi(50, 10, 1)))
m = zeros(length(val), 4000)
for k = 1 : length(val)
y = val(k);
num1 = randi(3500);
num2 = randi(4000);
index1 = min([num1, num2]);
index2 = max([num1, num2]);
plot([num1, num2], [y, y], 'b.-', 'LineWidth', 5, 'markerSize', 20)
hold on;
m(k, index1 : index2) = 1;
end
grid on
Med Future
2022년 3월 6일
편집: Med Future
2022년 3월 6일
Image Analyst
2022년 3월 6일
Try this:
val = sort(randi(1000, 200, 1));
m = zeros(length(val), 1000);
for k = 1 : length(val)
y = val(k);
num1 = randi(3500);
num2 = randi(4000);
index1 = min([num1, num2]);
index2 = max([num1, num2]);
plot([num1, num2], [y, y], 'b.-', 'LineWidth', 3, 'markerSize', 20)
hold on;
indexes = round([index1, index2] / 4) % Now go from 1-1000 instead of 1-4000
m(k, indexes) = y; % m is a 200 by 1000 array
end
grid on
Now you have a 200 row array where the value of the y height goes from index1 to index2. There are 1000 columns which indicate x going up to 4000.
Med Future
2022년 3월 6일
Image Analyst
2022년 3월 6일
Sorry, I tried, but now I'm heading out now to do some errands. Once you take that 2 hour training you'll be able to do it yourself. It sounds like it's a simple application of calling rand() or randi() and then using a for loop, something you'll be able to do after taking the 2 hour training. Good luck.
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