delate a specific number in an array and the number that have the index corresponding to the this number in an other array

If I have two array A and B:

A=[0,0,3,4,5,6,7,8,9,0]

B=[10,9,8,7,6,5,4,3,2,1]

I want to delate the 0 in A and the number that have the index corresponding to the 0 in B obtaining:

A=[3,4,5,6,7,8,9]

B=[8,7,6,5,4,3,2]

To do that I would do a cycle with an if. I imagine is a common problem. Is there a simpler way to do it?

Thanks

Answer 1

[Jan]

A=[0,0,3,4,5,6,7,8,9,0];
B=[10,9,8,7,6,5,4,3,2,1];

match = (A == 0);
A(match) = []
B(match) = []

Or the other way around:

match = (A ~= 0);
A = A(match)
B = B(match)

Answer 2

[David Hill]

A=[0,0,3,4,5,6,7,8,9,0];
B=[10,9,8,7,6,5,4,3,2,1];
idx=A==0;
A(idx)=[];
B(idx)=[];