loop in function inside
조회 수: 1 (최근 30일)
이전 댓글 표시
kk1
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
function y=f(theta,da)
for i=1:length(theta)
iter = 0;
for j=1:length(da)
iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
plot(da,y )
end
why this is not working how to make looping in function and find its derivative w r to da i.e df/dda with out syms and help to plot any one
댓글 수: 6
채택된 답변
Voss
2022년 1월 29일
You must call the function f() somwhere. Your code defined f() but never used it; that's why there was an empty plot: y was not updated.
kk1(); % here I am calling your main function kk1
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
% y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
y = f(theta,da); % here your main function kk1 is calling the nested function f
plot(da,y);
function y=f(theta,da)
y=zeros(length(theta),length(da));
for i=1:length(theta)
iter = 0;
for j=1:length(da)
% iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
end
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!