Number of rows based on frequency of one integer and position of another integer

조회 수: 3 (최근 30일)
Hello. I was wondering if someone could help me with this:
Let's say you have a 2000 x 2 matrix, where all the elements are integers. How can we count the number of rows that contain the number 10 in its first column and any number with the highest 5 integers in the second column?
In other words, the following but where X is the fifth highest number in the second column:
nnz(matrix(:,1) == 10 & matrix(:,2) > X);
EDIT -> Very importantly, the list with the highest 5 integers must be determined for each integer in the first column. So, if one wanted to do this for the number 10, it must be determining the highest 5 integers in the second column WHEN the integer in the first column is 10.
Thanks!

채택된 답변

Voss
Voss 2022년 1월 17일
Get the set of unique numbers in the 2nd column:
col2_vals = unique(matrix(:,2));
The 5th highest is 4th from the end. So, to match any number within the highest 5:
nnz(matrix(:,1) == 10 & matrix(:,2) >= col2_vals(end-4));
  댓글 수: 4
Voss
Voss 2022년 1월 18일
idx = matrix(:,1) == 10;
col2_vals = unique(matrix(idx,2)); % now: unique values of column 2 where column 1 is 10
nnz(matrix(idx,2) >= col2_vals(end-4));

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추가 답변 (1개)

David Hill
David Hill 2022년 1월 17일
r=unique(matrix(:,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
  댓글 수: 3
David Hill
David Hill 2022년 1월 18일
r=unique(matrix(matrix(:,1)==10,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
Neuro
Neuro 2022년 1월 18일
Thanks @David Hill, but it gives me an error message:
Error using unique (line 117)
Invalid input. Valid flags are 'rows', 'first', 'last', 'stable', 'sorted', 'legacy'.

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