Given: f(x) = exp(-x^2) on the interval [-1; 1].
Need to:
  1. Approximate f(x) by a 9-degree monomial basis polynomial interpolant with equidistant nodes. Proceed as follows:
1.1. create a vector x containing the n = 9 interpolation nodes.
1.2. use the function 'vander' to create the interpolation matrix G.
1.3. compute yi = f(xi) at the n interpolation nodes.
1.4. compute the n basis coefficients c.
2. Evaluate the accuracy of the interpolant, say f1, as follows:
2.1. Use the Matlab function 'polyval' to evaluate f1 for 100 evenly distributed points on [-1; 1].
2.2. Compare these interpolated values with the 'true' values of f.
2.3. Plot the approximation error.
So far, could this. But no idea whether they are correct or not. Don't even understand what should do in 2.2 and 2.3
f = @(x) exp(-x.^2);
n = 9;
y = linspace(-1, 1, n);
z = [];
for i = 1:length(y)
z(i) = feval(f,y(i));
end
v = fliplr(vander(y));
a = v\z';
b = a(end:-1:1)';
%5
c = linspace(-1,1);
d = polyval(b, c);
p = polyfit(c,d);

 채택된 답변

David Hill
David Hill 2021년 10월 11일

0 개 추천

Something like this.
f = @(x) exp(-x.^2);
x = linspace(-1, 1, 9);
G=vander(x);
y=f(x);
c=G\y';
f1=@(x)polyval(c,x);
t=linspace(-1,1,100);
Error=(f(t)-f1(t))./f(t);
plot(t,Error)

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Polynomials에 대해 자세히 알아보기

질문:

2021년 10월 11일

답변:

2021년 10월 11일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by