Split along word into parts with different lengths

조회 수: 7 (최근 30일)
Brasco , D.
Brasco , D. 2014년 6월 6일
편집: Brasco , D. 2016년 9월 1일
problem solved
  댓글 수: 3
Cedric
Cedric 2014년 6월 6일
I guess that it is not always starting with the same string, otherwise you wouldn't have to parse it. We need more examples, as well as a clear description of criteria which define sub parts.
dpb
dpb 2014년 6월 6일
Specifically, what's the rule for breaking down the first set of six letters into the two groups of three if that isn't a consistent string. If it is, then just substring referencing of 1:3 and 4:6 takes care of it.
The rest looks like looking for capitals after a lowercase letter.

댓글을 달려면 로그인하십시오.

채택된 답변

Cedric
Cedric 2014년 6월 6일
편집: Cedric 2014년 6월 6일
Here is a solution based on comments above. Yet, we will need you to answer these comments so we can refine the approach. Assuming
data = {'NCCINS.AttitudePositionINS1.Pitch', 'NCCINS.AttitudePositionINS1.Roll'} ;
we perform a single call to REGEXP on a comma-separated merger of the original strings, as follows:
pattern = '(\w{3})(\w{3}).(.[^A-Z]+)(.[^A-Z]+)([^\.]+).([^,]+)' ;
tokens = regexp( sprintf('%s,', data{:}), pattern, 'tokens' ) ;
with that, we get
>> tokens{1}
ans =
'NCC' 'INS' 'Attitude' 'Position' 'INS1' 'Pitch'
>> tokens{2}
ans =
'NCC' 'INS' 'Attitude' 'Position' 'INS1' 'Roll'
  댓글 수: 1
Cedric
Cedric 2014년 6월 6일
편집: Cedric 2014년 6월 6일
Can you attach a few example, or one package, or even the 70. The more I have, the more I can refine the approach. The approach above is based on regular expressions and pattern matching. I cannot explain it generally because there would be way too much to develop. Yet, once we have a pattern which suites your case specifically, I can explain it to you.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Characters and Strings에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by