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A way to speed up my custom interpolation algorithm?
I found yq = y(find(x <= xq, 1, 'last')) proposed by @Jonas works best for my usecase.
A way to speed up my custom interpolation algorithm?
I found yq = y(find(x <= xq, 1, 'last')) proposed by @Jonas works best for my usecase.
2년 초과 전 | 0
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A way to speed up my custom interpolation algorithm?
I'm writing a simulation program which often has to read out data from small data tables. The x and y values are provided as 1x...
2년 초과 전 | 답변 수: 2 | 0