Ashish Kumar
Followers: 0 Following: 0
Feeds
답변 있음
Finite potential well transcendental graph
clear all; e=1.6*10^-19; % eV to Joules V=10*e; L=1.8*10^(-9)/2; m=9.11e-31; h_bar=(6.63e-34)/(2*pi); a=(sqrt(2*m)*...
Finite potential well transcendental graph
clear all; e=1.6*10^-19; % eV to Joules V=10*e; L=1.8*10^(-9)/2; m=9.11e-31; h_bar=(6.63e-34)/(2*pi); a=(sqrt(2*m)*...
대략 2년 전 | 0