Feeds
질문
Should any error appear when different types of convolutions on same vectors compared?
Hi, I've got an assignment where I needed to check four types of convolution methods: linear, circular, Overlap add and Overl...
7년 초과 전 | 답변 수: 0 | 0
0
답변질문
How can I modify vector length?
I have several vectors to compare, however they all slightly differentiate by length. I know that first numbers of vectors are z...
7년 초과 전 | 답변 수: 1 | 0
1
답변답변 있음
How can I turn off a "self learning" function of Matlab?
Anyways, lots of thanks. Hope (JIT) will work.
How can I turn off a "self learning" function of Matlab?
Anyways, lots of thanks. Hope (JIT) will work.
7년 초과 전 | 0
답변 있음
How can I turn off a "self learning" function of Matlab?
I remember, that function name sounds like "unhealsh", but when I typed it in matlab help, it didn't find anything. Probably, I ...
How can I turn off a "self learning" function of Matlab?
I remember, that function name sounds like "unhealsh", but when I typed it in matlab help, it didn't find anything. Probably, I ...
7년 초과 전 | 0
질문
How can I turn off a "self learning" function of Matlab?
Hello, I've got an assignment where I was asked to compare time required for different convolutions methods. Surprisingly, t...
7년 초과 전 | 답변 수: 3 | 0
3
답변질문
Low pass filter using firpm and freqz functions
Hello, I've got an assignment, that requires to filter a Tuba from Picolo in an audiofile which is mp3 format. So, first I...
거의 8년 전 | 답변 수: 0 | 0
0
답변답변 있음
Hi, how can I calculate an impulse response of the LTI system, for a given function : y[n] - 0.5*y[n-1] = -0.5*x[n] + x[n-1]
Lots of thanks
Hi, how can I calculate an impulse response of the LTI system, for a given function : y[n] - 0.5*y[n-1] = -0.5*x[n] + x[n-1]
Lots of thanks
거의 8년 전 | 0
질문
Hi, how can I calculate an impulse response of the LTI system, for a given function : y[n] - 0.5*y[n-1] = -0.5*x[n] + x[n-1]
% create a symbolic expresion for y(n) and x(n) syms y(n) syms x(n) %define function for transform Z y(n)= 0.5*y(n-...
거의 8년 전 | 답변 수: 3 | 0

