Problem 470. Scoring for oriented dominoes

Created by Doug Hull

Solve Later

Given a list of ordered pairs, and the order they should be placed in a line, find the sum of the absolute values of the differences.

list = [1 2
        5 3
        2 4

order = [1 3 2]

yields: [1 2][2 4][5 3]
    or: abs(2-2) + abs(4-5)
    or:        0 + 1
    or: 1

Solve

Solution Stats

1408 Solutions
537 Solvers

Last Solution submitted on Jan 25, 2020

Last 200 Solutions

Problem Comments

2 Comments

2 Comments

CAM on 7 Feb 2014

Is Test #3 correct? When I solve it with pencil and paper, I get 15 instead of 14.
[5 4][1 2][2 4][7 5][4 8][4 5][1 6]
= -3 + 0 + 3 + -1 + -4 + -4
= 3+0+3+1+4+4
=15
Have I missed something?

Raymond Phan on 26 Jul 2014

No it's 14. With the ordering, you should get:
[5 4][1 2][2 4][4 8][1 6][4 5][7 5], and the sum is abs(4-1) + abs(2-2) + abs(4-4) + abs(8-1) + abs(6-4) + abs(5-7) = 3 + 0 + 0 + 7 + 2 + 2 = 14

Solution Comments

Solution 423132

1 Comment

1 Comment

Jack BLAIR on 27 Mar 2014

isnt the answer to test 3, 15?

Solution 71141

1 Comment

1 Comment

Aurelien Queffurust on 11 Apr 2012

This solution requires Neural Network Toolbox

Problem Recent Solvers537

Problem Tags

contest

Problem 470. Scoring for oriented dominoes

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers537

Suggested Problems

More from this Author52

Problem Tags

Problem 470. Scoring for oriented dominoes

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers537

Suggested Problems

More from this Author52

Problem Tags

Players