Problem 44500. Find the starting index of a consecutive condition
Given a logical vector v, and a positive integer n, return the smallest index i that satisfies:
all( v(i : i+n-1) ) == true
For Example,
v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); i = consecutiveFind(v, 4);
Then:
i = 6
If there is no sequence of n consecutive true, then i should be an empty array.
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1 Comment
Atsushi Ueno
on 16 Nov 2019
The test suite is not enough because it does not contain any case that the number of consecutive true bits is exactly same as n.
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