input -> matrix (n*m) with at least one element equal to NaN;
output -> matrix(p*m), the same matrix where we deleted the entire line containing NaN;
Additional test cases have been added.
you can use find function... easy
function y = removeNaN(x)
[n m] = size(x);
for i = 1 : n
maxx = max(isnan(x(i,:)));
if maxx ~= 1
y = (x(i,:))
What is Wrong With THis Code CAn SomeOne Tell ME
It looks like y will return only the last non-NaN row, instead of collecting all of them.
This solution doesn't necessarily work if there are any Inf elements in the matrix. Perhaps it would be best to add a test case where that is the case.
Prime factor digits
Spot the outlier
intersection of matrices
Colon operator of two vectors
07 - Common functions and indexing 3
Duplicate each element of a vector.
Create a matrix X, where each column is a shifted copy of the vector v
A quadrant matrix
First non-zero element in each column
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