uint64 equivalence
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The program I'm writing needs to compare 64 bit integers. However, matlab doesn't seem to know when two numbers are equivalent.
For example:
>> 4467577170595717377 == 4467577170595717887
ans =
1
>> 4467577170595717377 == 4467577170595717888
ans =
0
Does anyone have any idea why it might be doing this? The numbers are well within the bounds of uint64 and any two numbers between the first two are considered equivalent.
답변 (1개)
Titus Edelhofer
2011년 6월 20일
Hi,
you are comparing doubles (MATLAB's standard number format), not 64 bit integers.
x1=uint64(4467577170595717377)
x1 =
4467577170595717377
x2=uint64(4467577170595717887)
x2 =
4467577170595717887
x1==x2
ans =
0
Titus
댓글 수: 5
Walter Roberson
2011년 6월 20일
Caution: in at least some versions, uint64(4467577170595717377) would operate by constructing the double precision number that most closely matches 4467577170595717377, and then converting that to uint64.
For example in 2008b,
>> uint64(4467577170595717887)
ans =
4467577170595717632
Even sscanf() of the number might not work:
>> sscanf('4467577170595717887','%lu')
ans =
4.46757717059572e+18
Sean de Wolski
2011년 6월 20일
I was thinking you could use dec2bin, lop off the end bits and convert back using bin2dec but it has a limit of 52bits. You could probably write your own version that converts back directly to uint64.
Sean de Wolski
2011년 6월 20일
and probably write a uint64str2bin as well since you want to avoid all conversion to double.
Jan
2011년 6월 20일
@Walter: Thanks for mentioning this strange feature. The UINT64 support of Matlab has not been satisfactory for a long time.
Steve Eddins
2011년 6월 20일
@Jan, @Walter: The behavior Walter mentioned was fixed in R2010b. Then in R2011a, a core set of arithmetic and other functions was modified to work natively with uint64 and int64, including plus (+), minus (–), uminus (–), times (.*), rdivide (./), ldivide (.\), power (.^), rem, mod, bitcmp, any, all, sum, diff, colon (:), sign, accumarray, and bsxfun.
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