Disabling printing underscore as subscript in figures

Underscores print as subscript in figures. Can I disable it because I want to print the underscores as well.

Thanks.

[Michael Marcus]

Although this allows underscores to print, it does not allow special symbols such as \mum to work.. Does anyone know how to allow both.

Mike Marcus

[Michael Marcus]

I did find out another way to keep the underscore. \_ does work ? I have answered my own question? Convert all underscores in the text to \_ instead of changing the interpreter to none.

Answer 1

[Walter Roberson]

Set the Interpreter property for that field to 'none'; the default for text() fields is LaTex.

title('This_title has an underline', 'Interpreter', 'none'); % Also works with xlabel() and ylabel()

[AP]

Thank you very much.

h=gco(1);

set(h,'text','none')

[AP]

Why this does not work in the following for loop? :(

for i=1:4
    subplot(2,2,i)
    imshow(im{i})
    h=gco;
    set(h,'text','none');
    title(sprintf('%s_%d',mytitle{i},i))
end

It does not apply the change in text property and prints the subscript.

[Walter Roberson]

Personally I never count on gco being the object I am interested in.

In the above, gco is likely to be the result of imshow(), but imshow() returns an image object, and image objects do not have a 'text' field.

When you title(), a _new_ text object is created to hold the title. That new text object is not going to inherit the properties of the old one.

I would suggest,

for i = 1:4
    subplot(2,2,i)
    imshow(im{i})
    title(sprintf('%s_%d',mytitle{i},i), 'Interpreter', 'none');
end

[AP]

You're the best. Thanks.

[Jan]

Another method: Replace '_' by '\_' in the string.

[Hang Dong]

Thank you, this works.

[Addo]

How can I use this for the legend of a plot? I have a string with underscores that I would like to use for the legend. I don't want to change it to "\_" and 'Interpreter', 'none' doesn't work with legend('show').

[AM]

try something like this:

leg=legend('data1','data2','data3');
set(leg,'Interpreter', 'none')

[Walter Roberson]

@AM is correct: although legend() does not accept that name/value pair, you can set it on the handle.

[Yulong Li]

It looks like it does not work for stackedplot:

title(filename, 'Interpreter', 'none');

It returns error:

Error using matlab.graphics.chart.Chart/title

Too many input arguments specified when using title with stackedplot.

Is there a way to disable understcore in stackedplot title?

[Walter Roberson]

@Yulong Li

It appears that stackedplot treats titles differently. The great majority of plot types are within axes, and in those cases the axes has a Title property that is a text() object. But stackedplot() does not use axes: it is a direct parent of a figure, and the Title property for it is a character vector, with there being no Interpreter property.

It appears that you need to use the method suggested by @Jan in https://www.mathworks.com/matlabcentral/answers/9260-disabling-printing-underscore-as-subscript-in-figures#comment_20281 -- namely to replace the _ with \_

title(regexprep(filename, '_', '\\_'))

[Yulong Li]

@Walter Roberson got it, thanks!

Answer 2

[HE]

If you are using sprintf, \\_ should work for you.

Example from https://www.mathworks.com/matlabcentral/answers/94238-how-can-i-place-the-_-or-characters-in-a-text-command#comment_327816:

old_cells = sprintf('Old cells: Y = %3.3f (X) \\^ %1.3f',coefs_old);
young_cells = sprintf('Young cells: Y = %3.3f (X) \\^%1.3f',coefs_young);