Export transfer function model to workspace from Simulink without linmod
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I want to export the trasfer function of a simple simulink program to the workspace. I know it can be done simply by using the commands
[a,b,c,d]=linmod('model')
sys=ss(a,b,c,d);
tf(sys)
Is there any way to avoid the linmod command? The reason I need to do this is to present this method for people who are not familiar with state-sspace models.

댓글 수: 1
Azzi Abdelmalek
2013년 10월 18일
Lazaros commented
Isn't there anyone who can help me with this? Thanks again in advance!
답변 (1개)
Azzi Abdelmalek
2013년 10월 14일
편집: Azzi Abdelmalek
2013년 10월 14일
Edit
Your model name is transfer, and you have two transfer function named Transfer Fcn and Transfer Fcn1
To get the parameters of Transfer Fcn block
num=get_param('transfer/Transfer Fcn','Numerator');
den=get_param('transfer/Transfer Fcn','Denominator');
model=tf(str2num(num),str2num(den))
댓글 수: 8
Azzi Abdelmalek
2013년 10월 14일
Look at Edit
Lazaros Moysis
2013년 10월 14일
Azzi Abdelmalek
2013년 10월 14일
num=get_param('transfer/Transfer Fcn','Numerator');
den=get_param('transfer/Transfer Fcn','Denominator');
num1=get_param('transfer/Transfer Fcn1','Numerator');
den1=get_param('transfer/Transfer Fcn1','Denominator');
model=tf(str2num(num),str2num(den))
model1=tf(str2num(num1),str2num(den1))
modelg=model*model1
Lazaros Moysis
2013년 10월 14일
편집: Lazaros Moysis
2013년 10월 14일
Azzi Abdelmalek
2013년 10월 18일
When you read the help of linmod, nothing is referring to an equivalent function, which make me think there is not another way. I think also Its the way simulink stores your model (linear or non linerar), even when you use a transfer function, I think, simulink stores it as state space representation.
Lazaros Moysis
2013년 10월 18일
haryana thomas
2018년 8월 21일
you should type this command in the matlab command line.
plant = linearize('name of simulink model')
tf(plant)
Raja Singh R
2020년 8월 13일
Thomas, It is showing empty transfer function
카테고리
도움말 센터 및 File Exchange에서 Simulink에 대해 자세히 알아보기
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