Interpolation within a data table

I have a 12 X 12 table of Z-values, which are found against variable P(1:1:12) and X(25:25:300) as shown in table.I want to get the value of "Z" @ P=10.5 & X=115 via interpolation. your help is appreciated.

댓글 수: 6

sixwwwwww
sixwwwwww 2013년 10월 10일
You problem is not clear because if your first column is 1:1:12 then first element in table is 1 and if your first row is 100:25:300 then first element in table is 100. How you have two values at first element in table? Can you please share your table to find out solution
Jan
Jan 2013년 10월 10일
What exactly is "a table"?
am
am 2013년 10월 11일
Sorry, couldn't put it right. Here's the table and I have corrected my question too.
sixwwwwww
sixwwwwww 2013년 10월 12일
Hi can you send me the table?
Image Analyst
Image Analyst 2013년 10월 12일
편집: Image Analyst 2013년 10월 12일
Something is still not correct, despite your claim to have edited it to fix in. You say that the first column is x and is 100:25:300. Yet it seems to be 25:25:300 instead, since the numbers start at 25, not 100. Also the table is 13 columns if the first columns is X and there are 12 columns in addition to that. And if the first row is P and there are 12 rows in addition to that, then there are 13 rows, not 12. So is X and P actually columns/rows in the table as you said? Or are they separate column/row vectors and not part of the 12x12 table?
am
am 2013년 10월 12일
Pardon my ignorance, actually this is some experimental data & yes; X=(25:25:300) and P=1:1:12. The Z values are found against these two variables which is 12x12 table of Z values. So you can say X & P are separate column/row vectors (reference values for Z).

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답변 (1개)

Image Analyst
Image Analyst 2013년 10월 12일

0 개 추천

Why not just use bilinear interpolation: http://en.wikipedia.org/wiki/Bilinear_interpolation. It's easy, intuitive, and straightforward.

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질문:

am
2013년 10월 10일

편집:

am
2013년 10월 12일

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