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How to create column headers?

조회 수: 5(최근 30일)
Hannah
Hannah 2021년 8월 13일
댓글: Hannah 2021년 8월 16일
I have the following code:
months=1:12;
orientation = [0, -90];
row = 1:3;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
table.x=tilt;
table.y=irr;
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
disp([m,o,r])
for n=1:length(tilt)
table.x=tilt(n);
table.y=irr(n);
disp(table)
end
end
end
end
How can I have x and y as the column headers instaed of having them noting every element? for example for m=1,0=2,r=3, I want the output to be:
1 2 3
x y
0 10
10 110
20 120
30 130
40 140
50 150
60 160
70 170
80 180
90 190

채택된 답변

Scott MacKenzie
Scott MacKenzie 2021년 8월 13일
편집: Scott MacKenzie 2021년 8월 13일
Something like this will work. I'm only showing the inner for-loop.
fprintf('%6s%6s\n\n', 'x', 'y');
for n=1:length(tilt)
table.x=tilt(n);
table.y=irr(n);
disp([table.x table.y]);
end
Output (last table only):
12 2 3
x y
0 10
10 110
20 120
30 130
40 140
50 150
60 160
70 170
  댓글 수: 2
Scott MacKenzie
Scott MacKenzie 2021년 8월 13일
You're welcome. Glad to help. Good luck.

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추가 답변(1개)

Cris LaPierre
Cris LaPierre 2021년 8월 13일
My preference is to use the table function to create a MATLAB table (data type table instead of structure)
x = [0,10,20,30,40,50,60,70,80,90]';
y = [10,110,120,130,140,150,160,170,180,190]';
data = table(x,y)
data = 10×2 table
x y __ ___ 0 10 10 110 20 120 30 130 40 140 50 150 60 160 70 170 80 180 90 190
However, to stick to the same approach you are using, remove the last loop. I've reduced months and row to limit the output length here.
months=1:1;
orientation = [0, -90];
row = 1:1;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
disp([m,o,r])
table.x=tilt';
table.y=irr';
disp(["x","y"])
disp([table.x table.y])
end
end
end
1 1 1
"x" "y"
0 10 10 110 20 120 30 130 40 140 50 150 60 160 70 170 80 180 90 190
1 2 1
"x" "y"
0 10 10 110 20 120 30 130 40 140 50 150 60 160 70 170 80 180 90 190
To create exactly what you specified, you can use fprintf instead of disp
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
fprintf('%g %g %g',m,o,r)
fprintf('%s %s',"x","y")
table.x=tilt';
table.y=irr';
fprintf('%g %g\n',[table.x table.y]')
end
end
end
1 1 1
x y
0 10 10 110 20 120 30 130 40 140 50 150 60 160 70 170 80 180 90 190
1 2 1
x y
0 10 10 110 20 120 30 130 40 140 50 150 60 160 70 170 80 180 90 190
  댓글 수: 1
Hannah
Hannah 2021년 8월 16일
Yes that's great too. makes it nicer. Thank you so much!

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