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how can a make a loop for a double value in Matlab?

조회 수: 2(최근 30일)
DulceEien
DulceEien 2021년 8월 10일
댓글: DulceEien 2021년 8월 10일
when I obtain the data for the array I'm having the ID in a 22x1 double data, and when I run the if condition I have a problem with the size
"Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
for i = 1:length(T1.ID)
if ID(i) == 0
EI(i) = 'Very high';
elseif ID(i) == 1
EI(i) = 'High';
elseif ID(i) == 2
EI(i) = 'Medium';
elseif ID(i) == 3
EI(i) = 'Low';
end
end
the other values are taking a colum of the table generated. Sorry, I'm kind of new with matlab, thanks in advance

채택된 답변

Simon Chan
Simon Chan 2021년 8월 10일
I think it should put into a cell array:
EI = cell(1,length(T1.ID)); % Cell array
for i = 1:length(T1.ID)
if ID(i) == 0
EI{i} = 'Very high';
elseif ID(i) == 1
EI{i} = 'High';
elseif ID(i) == 2
EI{i} = 'Medium';
elseif ID(i) == 3
EI{i} = 'Low';
end
end
  댓글 수: 1
DulceEien
DulceEien 2021년 8월 10일
yes, this is working, thank yoou

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추가 답변(1개)

Scott MacKenzie
Scott MacKenzie 2021년 8월 10일
It's not clear what 19 variables you have in the table T1, but I suspect your error will disappear via...
for i = 1:length(ID) % change from T1.ID to just ID
if ID(i) == 0
EI(i) = 'Very high';
elseif ID(i) == 1
EI(i) = 'High';
elseif ID(i) == 2
EI(i) = 'Medium';
elseif ID(i) == 3
EI(i) = 'Low';
end
end

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