Find count of repeated letters (sequence)
이전 댓글 표시
Sir,
How to find the no. of repeated sequence (letters) in the given sentence.
for example, a="I want THAAAAAT APPPPPLE ):):): totally unprepared";
The No. of repeated sequences are: 3
ie.,
1. THAAAAAT
2. APPPPPLE
3. ):):):
thanks
댓글 수: 4
Walter Roberson
2013년 10월 8일
'THAAAAAT' is not a repeated sequence. It contains a repeated sequence.
Could you confirm that the sequences can be more than just adjacent letters such as the A's in THAAAAAT ? The '):' repeating as a unit is intended to be noticed?
Jothi
2013년 10월 9일
Walter Roberson
2013년 10월 9일
Your #3, ):):): does not have continuously repeated symbols.
If the repeated sequences are to be identified, then why would all of THAAAAAT be output, and not just AAAAA ?
Jothi
2013년 10월 9일
답변 (2개)
Try to understand the following and fine-tune it to your needs:
n = sum( diff([0, diff(a)==0]) == 1 )
In particular, evaluate
diff(a)==0
and see how your problem actually translates into counting clusters of the outcome of diff(a)==0.
댓글 수: 4
Just to be sure, the repeated sequences are:
AAAAA
PPPPP
ll (in 'totally')
is that right? If so, then my answer works.
Jothi
2013년 10월 10일
You seem to indicate that one repeated sequence is '):'. As far as I am concerned, there is no simple generic solution if you want to detect repeated, arbitrary patterns. To illustrate,
'AABBCCDDEEFFAABBCCDDEEFF'
Here, repeated patterns are
'AA', 'BB', .., 'FF', 'AABB', 'BBCC', .., 'AABBCC', 'BBCCDD', ..,
'AABBCCDD', 'BBCCDDEE', .., 'AABBCCDDEEFF'
Using regular expressions, we can probably get some solution but it will be prohibitively time consuming.
Sean de Wolski
2013년 10월 10일
Yeah, every emoticon would have to be predefined. For the chatroom we use here there are even word emoticons like (b) which inserts a frosty beer mug or (ply) which inserts an image of a playing card.
Walter Roberson
2016년 12월 1일
a='I want THAAAAAT APPPPPLE ):):): totally unprepared';
regexp(a, '(.+)\1{2,}', 'match')
ans =
1×3 cell array
'AAAAA' 'PPPPP' '):):):'
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